如何从 mysql 数据库构建 JSON 数组

php json mysql

2022-08-30 14:28:05

好吧，我一直在绞尽脑汁地试图从mysql构建一个JSON数组。数组必须采用以下格式。我正在使用完整日历，并希望使日历上的事件动态化。下面是构建数组的代码，但目前它尚未从mysql获取信息

$year = date('Y');
$month = date('m');

echo json_encode(array(

    //Each array below must be pulled from database
        //1st record
        array(
        'id' => 111,
        'title' => "Event1",
        'start' => "$year-$month-10",
        'url' => "http://yahoo.com/"
    ),

         //2nd record
         array(
        'id' => 222,
        'title' => "Event2",
        'start' => "$year-$month-20",
        'end' => "$year-$month-22",
        'url' => "http://yahoo.com/"
    )

));

答案 1

像这样的事情是你想做的吗？

$return_arr = array();

$fetch = mysql_query("SELECT * FROM table"); 

while ($row = mysql_fetch_array($fetch, MYSQL_ASSOC)) {
    $row_array['id'] = $row['id'];
    $row_array['col1'] = $row['col1'];
    $row_array['col2'] = $row['col2'];

    array_push($return_arr,$row_array);
}

echo json_encode($return_arr);

它返回以下格式的 json 字符串：

[{"id":"1","col1":"col1_value","col2":"col2_value"},{"id":"2","col1":"col1_value","col2":"col2_value"}]

或者类似这样的东西：

$year = date('Y');
$month = date('m');

$json_array = array(

//Each array below must be pulled from database
    //1st record
    array(
    'id' => 111,
    'title' => "Event1",
    'start' => "$year-$month-10",
    'url' => "http://yahoo.com/"
),

     //2nd record
     array(
    'id' => 222,
    'title' => "Event2",
    'start' => "$year-$month-20",
    'end' => "$year-$month-22",
    'url' => "http://yahoo.com/"
)

);

echo json_encode($json_array);

答案 2

PDO解决方案，只是为了更好的实现，然后：mysql_*

$array = $pdo->query("SELECT id, title, '$year-month-10' as start,url 
  FROM table")->fetchAll(PDO::FETCH_ASSOC);
echo json_encode($array);

不错的功能还在于它将整数保留为整数而不是字符串。