如何在安卓中为年龄计算方法创建方法

android java

2022-09-02 22:47:45

我想写一个从出生日期计算年龄的方法，逻辑是否正确以及如何用android Java编写它：

public int calculateAge(String birthday){ 
 // consider that birthday format is ddmmyyyy;

 String today = SystemDate(ddmmyyyy);
 int bDay = birthday(1,2).toInteger;
 int bMonth = birthday(3,4).toInteger;
 int bYear = birhtday(5,8).toInteger;

 int tDay = today(1,2).toInteger;
 int tMonth = today(3,4).toInteger;
 int tYear = today(5,8).toInteger;

 if (tMonth == bMonth){
     if (tday>= bDay){ 
        age = tYear - bYear;
      else 
        age = tYear - bYear - 1;}
 else
   if (tMonth > bMonth) {
       age = tYear - bYear;
   else 
       age = tYear - bYear - 1;}
 }
 return age;
}

答案 1

以下是我对这个问题的解决方案：

/**
 * Method to extract the user's age from the entered Date of Birth.
 * 
 * @param DoB String The user's date of birth.
 * 
 * @return ageS String The user's age in years based on the supplied DoB.
 */
private String getAge(int year, int month, int day){
    Calendar dob = Calendar.getInstance();
    Calendar today = Calendar.getInstance();

    dob.set(year, month, day); 

    int age = today.get(Calendar.YEAR) - dob.get(Calendar.YEAR);

    if (today.get(Calendar.DAY_OF_YEAR) < dob.get(Calendar.DAY_OF_YEAR)){
        age--; 
    }

    Integer ageInt = new Integer(age);
    String ageS = ageInt.toString();

    return ageS;  
}

我使用 DatePicker 来获取此处所需的输入值。此方法与日期选取器一起专门用于获取用户的 DoB 并计算其年龄。可以稍作修改以允许用户 DoB 的字符串输入，具体取决于您的特定实现。String的返回类型用于更新TextView，可以进行轻微的修改以允许类型输出。int

答案 2

这很完美.....

public int getAge(int DOByear, int DOBmonth, int DOBday) {

        int age;

        final Calendar calenderToday = Calendar.getInstance();
        int currentYear = calenderToday.get(Calendar.YEAR);
        int currentMonth = 1 + calenderToday.get(Calendar.MONTH);
        int todayDay = calenderToday.get(Calendar.DAY_OF_MONTH);

        age = currentYear - DOByear;

        if(DOBmonth > currentMonth) {
            --age;
        } else if(DOBmonth == currentMonth) {
            if(DOBday > todayDay){
                --age;
            }
        }
        return age;
    }